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急求!将下列PAsCAl语言代码转换为C++

#include <iostream>#include <string>using std::cout;using std::cin;using std::endl;using std::string;int dectobinary(int dec,string &bin){ int len=0; while(dec!=0) { bin=(dec%2?'1':'0')+bin; ++len; dec=dec/2; } return len;}int main(){ int n,len; string bin=

#include#include#includeint main(){ const Array t{2,3,5,7}; Array bj; bj.fill(0);bj[2]=1;bj[3]=1;bj[5]=1;bj[7]=1; int y=0; for(int a=0;a 评论0 0 0

void change(int c, int b){ if (c[m])=2147000000 printf("NO number"); else { for (int i=1 ; i0)&&(j>0)) if (c[j]==c[j-t[i]]+1) { s[i]++; j-=T[i]; } else i--; }}

#include <iostream>#include <stdlib.h>#include <cmath>using namespace std;const double zero=1e-11;float f(float m,float n,float p,float x){ return (exp(x*log(m))+exp(x*log(n))-exp(x*log(p)));}int main(){ float a,b,x,fa,fx; int m,n,p; freopen("equation.in

假如你用了std的话,那就while(cin>>t);如果只是c风格的输入,就为while(scanf("%d",&t)!=EOF)或者while(scanf("%d",&t)!=-1)都行

#include <istream>#include <cstdio>using namespace std;long long sum[2000][2000],x[2000][2000],y[2000][2000];int d[2000],w[2000];int n,c;long long min(long long a,long long b){ if (a>b) return(b); else return(a);}int init(){ int i; freopen("read.in",

procedure InOrder(var root:integer)if root thenbeginInOrder(l[root]);if root then write(root,' ');InOrder(r[root]);end;end;

var i,j,k,swap,nAllStatus,g_Height,g_Width:integer;DP:array[1..1000,1..1000]of integer;procedure swap1(g_Height,g_Width:integer);var tmp:integer;begin tmp:=g_Height; g_Height:=g_Width; g_Width:=tmp;end;function TestFirstLine(nStatus:integer

//p12-3.c#include #include //int a,b,c,d;没用int X,x0,x1,x2,x3,x4;int number(int a,int b,int c,int d){ int n1,n2,n3

pascal是标准教学语言,语法规则很严谨,向C转换很简单啊,自己看看C的语法收就可以了,begin ,end -> {}:= -> =x[a,b] -> x[a][b]if then -> c没有then 直接 if {}for -> for ( 初始表达是,终止判断;循环) {}case -> switch等等,

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